![]() In this tutorial, you have learned how to create an SQLite database on disk and in memory from a Python program using sqlite3 module. import sqlite3ĭef create_connection (): """ create a database connection to a database that residesĬreate_connection() Code language: Python ( python ) The following program creates an SQLite database in the memory. If you pass the file name as :memory: to the connect() function of the sqlite3 module, it will create a new database that resides in the memory (RAM) instead of a database file on disk. If you skip the folder path c:\sqlite\db, the program will create the database file in the current working directory (CWD). Let’s run the program and check the c:\sqlite\db folder. Note that the prefix r in the r"C:\sqlite\db\pythonsqlite.db" instructs Python that we are passing a raw string. Second, we pass the path of the database file to the create_connection() function to create the database. It is a good programming practice that you should always close the database connection when you complete with it. If everything is fine, we display the SQLite database version. In case an error occurs, we catch it within the try except block and display the error message. By using the Connection object, you can perform various database operations. It returns a Connection object that represents the database. The connect() function opens a connection to an SQLite database. Inside the function, we call the connect() function of the sqlite3 module. import sqlite3ĭef create_connection (db_file): """ create a database connection to a SQLite database """Ĭreate_connection( r"C:\sqlite\db\pythonsqlite.db")įirst, we define a function called create_connection() that connects to an SQLite database specified by the database file db_file. Or you can place the database file a folder of your choice. To update the data in your database, you need to perform the UPDATE operation on the database column. ![]() Note that you must create the c:\sqlite\db folder first before you execute the program. However, it is still not going to update the actual data in the database because SELECT only queries the data and REPLACE is performed on the queried copy of the data.
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